| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 2 | |
| 7 | |
| 10 | |
| 5 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5
13 members of a bridal party need transported to a wedding reception but there are only 4 2-passenger taxis available to take them. How many will need to find other transportation?
| 7 | |
| 5 | |
| 2 | |
| 3 |
There are 4 2-passenger taxis available so that's 4 x 2 = 8 total seats. There are 13 people needing transportation leaving 13 - 8 = 5 who will have to find other transportation.
If a mayor is elected with 86% of the votes cast and 62% of a town's 23,000 voters cast a vote, how many votes did the mayor receive?
| 10,980 | |
| 12,264 | |
| 7,415 | |
| 8,984 |
If 62% of the town's 23,000 voters cast ballots the number of votes cast is:
(\( \frac{62}{100} \)) x 23,000 = \( \frac{1,426,000}{100} \) = 14,260
The mayor got 86% of the votes cast which is:
(\( \frac{86}{100} \)) x 14,260 = \( \frac{1,226,360}{100} \) = 12,264 votes.
If \( \left|a - 2\right| \) - 9 = 0, which of these is a possible value for a?
| 8 | |
| -5 | |
| 7 | |
| -7 |
First, solve for \( \left|a - 2\right| \):
\( \left|a - 2\right| \) - 9 = 0
\( \left|a - 2\right| \) = 0 + 9
\( \left|a - 2\right| \) = 9
The value inside the absolute value brackets can be either positive or negative so (a - 2) must equal + 9 or -9 for \( \left|a - 2\right| \) to equal 9:
| a - 2 = 9 a = 9 + 2 a = 11 | a - 2 = -9 a = -9 + 2 a = -7 |
So, a = -7 or a = 11.
4! = ?
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.