| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 5:6 | |
| 9:2 | |
| 5:1 | |
| 49:2 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
What is \( \frac{-3y^6}{6y^4} \)?
| -2y2 | |
| -\(\frac{1}{2}\)y2 | |
| -\(\frac{1}{2}\)y24 | |
| -2y10 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-3y^6}{6y^4} \)
\( \frac{-3}{6} \) y(6 - 4)
-\(\frac{1}{2}\)y2
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Charlie buys two shirts, each with a regular price of $48, how much will he pay for both shirts?
| $52.80 | |
| $91.20 | |
| $4.80 | |
| $43.20 |
By buying two shirts, Charlie will save $48 x \( \frac{10}{100} \) = \( \frac{$48 x 10}{100} \) = \( \frac{$480}{100} \) = $4.80 on the second shirt.
So, his total cost will be
$48.00 + ($48.00 - $4.80)
$48.00 + $43.20
$91.20
Convert z-5 to remove the negative exponent.
| \( \frac{1}{z^5} \) | |
| \( \frac{5}{z} \) | |
| \( \frac{-1}{-5z^{5}} \) | |
| \( \frac{1}{z^{-5}} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.