| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
What is 5\( \sqrt{4} \) x 6\( \sqrt{4} \)?
| 30\( \sqrt{4} \) | |
| 30\( \sqrt{8} \) | |
| 120 | |
| 11\( \sqrt{16} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
5\( \sqrt{4} \) x 6\( \sqrt{4} \)
(5 x 6)\( \sqrt{4 \times 4} \)
30\( \sqrt{16} \)
Now we need to simplify the radical:
30\( \sqrt{16} \)
30\( \sqrt{4^2} \)
(30)(4)
120
Find the average of the following numbers: 11, 5, 11, 5.
| 3 | |
| 8 | |
| 13 | |
| 4 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{11 + 5 + 11 + 5}{4} \) = \( \frac{32}{4} \) = 8
18 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 7 | |
| 5 | |
| 2 |
There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 18 people needing transportation leaving 18 - 16 = 2 who will have to find other transportation.
What is \( 5 \)\( \sqrt{75} \) - \( 9 \)\( \sqrt{3} \)
| -4\( \sqrt{25} \) | |
| 45\( \sqrt{25} \) | |
| 16\( \sqrt{3} \) | |
| -4\( \sqrt{225} \) |
To subtract these radicals together their radicands must be the same:
5\( \sqrt{75} \) - 9\( \sqrt{3} \)
5\( \sqrt{25 \times 3} \) - 9\( \sqrt{3} \)
5\( \sqrt{5^2 \times 3} \) - 9\( \sqrt{3} \)
(5)(5)\( \sqrt{3} \) - 9\( \sqrt{3} \)
25\( \sqrt{3} \) - 9\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
25\( \sqrt{3} \) - 9\( \sqrt{3} \)What is -z2 - 3z2?
| 4z2 | |
| 2z4 | |
| 2z-4 | |
| -4z2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-1z2 - 3z2
(-1 - 3)z2
-4z2