ASVAB Arithmetic Reasoning Practice Test 934834 Results

	Your Results	Global Average
Questions	5	5
Correct	0	2.69
Score	0%	54%

Review

Damon loaned Betty $600 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$642
	$630
	$618
	$648

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $600
i = 0.03 x $600

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $600 + $18
total = $618

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

	greatest common factor
	absolute value
	least common multiple
	least common factor

Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.

What is $ 9 $$ \sqrt{50} $ - $ 2 $$ \sqrt{2} $

39% Answer Correctly

	18$ \sqrt{25} $
	7$ \sqrt{-21} $
	7$ \sqrt{50} $
	43$ \sqrt{2} $

Solution

To subtract these radicals together their radicands must be the same:

9$ \sqrt{50} $ - 2$ \sqrt{2} $
9$ \sqrt{25 \times 2} $ - 2$ \sqrt{2} $
9$ \sqrt{5^2 \times 2} $ - 2$ \sqrt{2} $
(9)(5)$ \sqrt{2} $ - 2$ \sqrt{2} $
45$ \sqrt{2} $ - 2$ \sqrt{2} $

Now that the radicands are identical, you can subtract them:

45$ \sqrt{2} $ - 2$ \sqrt{2} $
(45 - 2)$ \sqrt{2} $
43$ \sqrt{2} $

Convert 0.0000476 to scientific notation.

62% Answer Correctly

	4.76 x 10⁶
	4.76 x 10⁵
	47.6 x 10^-6
	4.76 x 10^-5

Solution

A number in scientific notation has the format 0.000 x 10^exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0000476 in scientific notation is 4.76 x 10^-5

Cooks are needed to prepare for a large party. Each cook can bake either 5 large cakes or 11 small cakes per hour. The kitchen is available for 3 hours and 37 large cakes and 290 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly

	11
	6
	12
	9

Solution

If a single cook can bake 5 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 5 x 3 = 15 large cakes during that time. 37 large cakes are needed for the party so $ \frac{37}{15} $ = 2$\frac{7}{15}$ cooks are needed to bake the required number of large cakes.

If a single cook can bake 11 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 11 x 3 = 33 small cakes during that time. 290 small cakes are needed for the party so $ \frac{290}{33} $ = 8$\frac{26}{33}$ cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 9 = 12 cooks.

	18\( \sqrt{25} \)
	7\( \sqrt{-21} \)
	7\( \sqrt{50} \)
	43\( \sqrt{2} \)