By buying two shirts, Ezra will save $29 x \( \frac{5}{100} \) = \( \frac{$29 x 5}{100} \) = \( \frac{$145}{100} \) = $1.45 on the second shirt.

1

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{2!} \)
\( \frac{3 \times 2 \times 1}{2 \times 1} \)
\( \frac{3}{1} \)
3

If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 40 large cakes are needed for the party so \( \frac{40}{8} \) = 5 cooks are needed to bake the required number of large cakes.

If a single cook can bake 13 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 13 x 4 = 52 small cakes during that time. 190 small cakes are needed for the party so \( \frac{190}{52} \) = 3\(\frac{17}{26}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 4 = 9 cooks.

To add these radicals together their radicands must be the same:

9\( \sqrt{8} \) + 8\( \sqrt{2} \)
9\( \sqrt{4 \times 2} \) + 8\( \sqrt{2} \)
9\( \sqrt{2^2 \times 2} \) + 8\( \sqrt{2} \)
(9)(2)\( \sqrt{2} \) + 8\( \sqrt{2} \)
18\( \sqrt{2} \) + 8\( \sqrt{2} \)

Now that the radicands are identical, you can add them together: