| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Alex buys two shirts, each with a regular price of $48, how much will he pay for both shirts?
| $69.60 | |
| $60.00 | |
| $84.00 | |
| $12.00 |
By buying two shirts, Alex will save $48 x \( \frac{25}{100} \) = \( \frac{$48 x 25}{100} \) = \( \frac{$1200}{100} \) = $12.00 on the second shirt.
So, his total cost will be
$48.00 + ($48.00 - $12.00)
$48.00 + $36.00
$84.00
Which of the following is an improper fraction?
\({a \over 5} \) |
|
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Simplify \( \frac{24}{56} \).
| \( \frac{4}{15} \) | |
| \( \frac{9}{19} \) | |
| \( \frac{3}{7} \) | |
| \( \frac{5}{16} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 24 are [1, 2, 3, 4, 6, 8, 12, 24] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{24}{56} \) = \( \frac{\frac{24}{8}}{\frac{56}{8}} \) = \( \frac{3}{7} \)
If \( \left|b + 9\right| \) + 5 = 3, which of these is a possible value for b?
| 11 | |
| 4 | |
| -7 | |
| -3 |
First, solve for \( \left|b + 9\right| \):
\( \left|b + 9\right| \) + 5 = 3
\( \left|b + 9\right| \) = 3 - 5
\( \left|b + 9\right| \) = -2
The value inside the absolute value brackets can be either positive or negative so (b + 9) must equal - 2 or --2 for \( \left|b + 9\right| \) to equal -2:
| b + 9 = -2 b = -2 - 9 b = -11 | b + 9 = 2 b = 2 - 9 b = -7 |
So, b = -7 or b = -11.
If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 6 | |
| 14 | |
| 9 | |
| 5 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 21 - 15 = 6 new staff for the busy season.