| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
Which of these numbers is a factor of 16?
| 18 | |
| 9 | |
| 4 | |
| 10 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 16 are 1, 2, 4, 8, 16.
What is \( \sqrt{\frac{4}{4}} \)?
| 1 | |
| \(\frac{4}{7}\) | |
| 1\(\frac{2}{7}\) | |
| 1\(\frac{3}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{4}{4}} \)
\( \frac{\sqrt{4}}{\sqrt{4}} \)
\( \frac{\sqrt{2^2}}{\sqrt{2^2}} \)
1
What is \( \frac{9b^5}{5b^2} \)?
| 1\(\frac{4}{5}\)b2\(\frac{1}{2}\) | |
| 1\(\frac{4}{5}\)b3 | |
| 1\(\frac{4}{5}\)b10 | |
| \(\frac{5}{9}\)b-3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{9b^5}{5b^2} \)
\( \frac{9}{5} \) b(5 - 2)
1\(\frac{4}{5}\)b3
If \( \left|x - 5\right| \) - 4 = -2, which of these is a possible value for x?
| 3 | |
| -11 | |
| -9 | |
| -8 |
First, solve for \( \left|x - 5\right| \):
\( \left|x - 5\right| \) - 4 = -2
\( \left|x - 5\right| \) = -2 + 4
\( \left|x - 5\right| \) = 2
The value inside the absolute value brackets can be either positive or negative so (x - 5) must equal + 2 or -2 for \( \left|x - 5\right| \) to equal 2:
| x - 5 = 2 x = 2 + 5 x = 7 | x - 5 = -2 x = -2 + 5 x = 3 |
So, x = 3 or x = 7.
| 1.6 | |
| 4.0 | |
| 1 | |
| 2.0 |
1