| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 20 small cakes per hour. The kitchen is available for 4 hours and 21 large cakes and 380 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 12 | |
| 6 | |
| 7 | |
| 8 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 21 large cakes are needed for the party so \( \frac{21}{8} \) = 2\(\frac{5}{8}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 20 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 20 x 4 = 80 small cakes during that time. 380 small cakes are needed for the party so \( \frac{380}{80} \) = 4\(\frac{3}{4}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 5 = 8 cooks.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 38 | |
| 37 | |
| 32 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
Solve for \( \frac{2!}{5!} \)
| \( \frac{1}{60480} \) | |
| 30 | |
| \( \frac{1}{60} \) | |
| \( \frac{1}{7} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{5!} \)
\( \frac{2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4 \times 3} \)
\( \frac{1}{60} \)
Monica scored 86% on her final exam. If each question was worth 4 points and there were 320 possible points on the exam, how many questions did Monica answer correctly?
| 81 | |
| 84 | |
| 69 | |
| 61 |
Monica scored 86% on the test meaning she earned 86% of the possible points on the test. There were 320 possible points on the test so she earned 320 x 0.86 = 276 points. Each question is worth 4 points so she got \( \frac{276}{4} \) = 69 questions right.
What is -5z6 x z5?
| -5z | |
| -5z30 | |
| -5z-1 | |
| -5z11 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-5z6 x z5
(-5 x 1)z(6 + 5)
-5z11