| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.73 |
| Score | 0% | 75% |
If a car travels 20 miles in 1 hour, what is the average speed?
| 65 mph | |
| 55 mph | |
| 15 mph | |
| 20 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solve 5 + (2 + 2) ÷ 4 x 3 - 32
| -1 | |
| 1\(\frac{1}{4}\) | |
| 1\(\frac{3}{4}\) | |
| 1\(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (2 + 2) ÷ 4 x 3 - 32
P: 5 + (4) ÷ 4 x 3 - 32
E: 5 + 4 ÷ 4 x 3 - 9
MD: 5 + \( \frac{4}{4} \) x 3 - 9
MD: 5 + \( \frac{12}{4} \) - 9
AS: \( \frac{20}{4} \) + \( \frac{12}{4} \) - 9
AS: \( \frac{32}{4} \) - 9
AS: \( \frac{32 - 36}{4} \)
\( \frac{-4}{4} \)
-1
17 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 9 | |
| 5 | |
| 7 | |
| 8 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 17 people needing transportation leaving 17 - 12 = 5 who will have to find other transportation.
4! = ?
5 x 4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is the greatest common factor of 44 and 64?
| 7 | |
| 27 | |
| 4 | |
| 40 |
The factors of 44 are [1, 2, 4, 11, 22, 44] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 3 factors [1, 2, 4] making 4 the greatest factor 44 and 64 have in common.