A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{9 + 3 + 10 + 2}{4} \) = \( \frac{24}{4} \) = 6

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{45}{100} \) = \( \frac{45 x 15}{100} \) = \( \frac{675}{100} \) = 6 shots

The center makes 35% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{6}{\frac{35}{100}} \) = 6 x \( \frac{100}{35} \) = \( \frac{6 x 100}{35} \) = \( \frac{600}{35} \) = 17 shots

to make the same number of shots as the guard and thus score the same number of points.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 4) ÷ 2 x 5 - 3²
P: 4 + (7) ÷ 2 x 5 - 3²
E: 4 + 7 ÷ 2 x 5 - 9
MD: 4 + \( \frac{7}{2} \) x 5 - 9
MD: 4 + \( \frac{35}{2} \) - 9
AS: \( \frac{8}{2} \) + \( \frac{35}{2} \) - 9
AS: \( \frac{43}{2} \) - 9
AS: \( \frac{43 - 18}{2} \)
\( \frac{25}{2} \)
12\(\frac{1}{2}\)

To subtract these radicals together their radicands must be the same:

4\( \sqrt{50} \) - 6\( \sqrt{2} \)
4\( \sqrt{25 \times 2} \) - 6\( \sqrt{2} \)
4\( \sqrt{5^2 \times 2} \) - 6\( \sqrt{2} \)
(4)(5)\( \sqrt{2} \) - 6\( \sqrt{2} \)
20\( \sqrt{2} \) - 6\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them: