| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
Which of the following is not an integer?
\({1 \over 2}\) |
|
-1 |
|
0 |
|
1 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
A bread recipe calls for 3\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?
| 2 cups | |
| 3 cups | |
| 1\(\frac{5}{8}\) cups | |
| \(\frac{7}{8}\) cups |
The amount of flour you need is (3\(\frac{1}{8}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{25}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups
Which of these numbers is a factor of 36?
| 22 | |
| 33 | |
| 36 | |
| 3 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.
The __________ is the greatest factor that divides two integers.
absolute value |
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greatest common multiple |
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greatest common factor |
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least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?
| 10 | |
| 6 | |
| 14 | |
| 8 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 5 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 5 x 3 = 15 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 15 - 9 = 6 new staff for the busy season.