| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
Latoya scored 78% on her final exam. If each question was worth 2 points and there were 80 possible points on the exam, how many questions did Latoya answer correctly?
| 37 | |
| 31 | |
| 36 | |
| 25 |
Latoya scored 78% on the test meaning she earned 78% of the possible points on the test. There were 80 possible points on the test so she earned 80 x 0.78 = 62 points. Each question is worth 2 points so she got \( \frac{62}{2} \) = 31 questions right.
19 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 7 | |
| 5 | |
| 6 |
There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 19 people needing transportation leaving 19 - 16 = 3 who will have to find other transportation.
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
distributive |
|
PEDMAS |
|
associative |
|
commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
What is 9\( \sqrt{5} \) x 6\( \sqrt{4} \)?
| 54\( \sqrt{4} \) | |
| 108\( \sqrt{5} \) | |
| 15\( \sqrt{4} \) | |
| 54\( \sqrt{5} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{5} \) x 6\( \sqrt{4} \)
(9 x 6)\( \sqrt{5 \times 4} \)
54\( \sqrt{20} \)
Now we need to simplify the radical:
54\( \sqrt{20} \)
54\( \sqrt{5 \times 4} \)
54\( \sqrt{5 \times 2^2} \)
(54)(2)\( \sqrt{5} \)
108\( \sqrt{5} \)
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 53 | |
| 42 | |
| 48 | |
| 46 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46