ASVAB Arithmetic Reasoning Practice Test 94705 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

Latoya scored 78% on her final exam. If each question was worth 2 points and there were 80 possible points on the exam, how many questions did Latoya answer correctly?

57% Answer Correctly
37
31
36
25

Solution

Latoya scored 78% on the test meaning she earned 78% of the possible points on the test. There were 80 possible points on the test so she earned 80 x 0.78 = 62 points. Each question is worth 2 points so she got \( \frac{62}{2} \) = 31 questions right.


2

19 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
3
7
5
6

Solution

There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 19 people needing transportation leaving 19 - 16 = 3 who will have to find other transportation.


3

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

59% Answer Correctly

distributive

PEDMAS

associative

commutative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


4

What is 9\( \sqrt{5} \) x 6\( \sqrt{4} \)?

41% Answer Correctly
54\( \sqrt{4} \)
108\( \sqrt{5} \)
15\( \sqrt{4} \)
54\( \sqrt{5} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

9\( \sqrt{5} \) x 6\( \sqrt{4} \)
(9 x 6)\( \sqrt{5 \times 4} \)
54\( \sqrt{20} \)

Now we need to simplify the radical:

54\( \sqrt{20} \)
54\( \sqrt{5 \times 4} \)
54\( \sqrt{5 \times 2^2} \)
(54)(2)\( \sqrt{5} \)
108\( \sqrt{5} \)


5

What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?

68% Answer Correctly
53
42
48
46

Solution

The equation for this sequence is:

an = an-1 + 3(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46