| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
What is the distance in miles of a trip that takes 8 hours at an average speed of 15 miles per hour?
| 80 miles | |
| 240 miles | |
| 420 miles | |
| 120 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 15mph \times 8h \)
120 miles
What is 5\( \sqrt{2} \) x 2\( \sqrt{3} \)?
| 10\( \sqrt{3} \) | |
| 10\( \sqrt{6} \) | |
| 7\( \sqrt{3} \) | |
| 7\( \sqrt{2} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
5\( \sqrt{2} \) x 2\( \sqrt{3} \)
(5 x 2)\( \sqrt{2 \times 3} \)
10\( \sqrt{6} \)
How many 1 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 8 | |
| 7 | |
| 4 | |
| 6 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{4 \text{ gallons}}{1 \text{ gallons}} \) = 4
If a rectangle is twice as long as it is wide and has a perimeter of 6 meters, what is the area of the rectangle?
| 162 m2 | |
| 8 m2 | |
| 32 m2 | |
| 2 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.
Putting these two equations together and solving for width (w):
2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1
Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m2
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 69 | |
| 61 | |
| 65 | |
| 55 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61