| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
A triathlon course includes a 100m swim, a 40.9km bike ride, and a 8.0km run. What is the total length of the race course?
| 55.1km | |
| 59.3km | |
| 66.5km | |
| 49km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 40.9km + 8.0km
total distance = 49km
A bread recipe calls for 3\(\frac{3}{4}\) cups of flour. If you only have 1 cup, how much more flour is needed?
| 2\(\frac{3}{4}\) cups | |
| 3\(\frac{1}{8}\) cups | |
| 3\(\frac{3}{8}\) cups | |
| 2\(\frac{1}{2}\) cups |
The amount of flour you need is (3\(\frac{3}{4}\) - 1) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{30}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{22}{8} \) cups
2\(\frac{3}{4}\) cups
A tiger in a zoo has consumed 117 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 195 pounds?
| 10 | |
| 5 | |
| 1 | |
| 6 |
If the tiger has consumed 117 pounds of food in 9 days that's \( \frac{117}{9} \) = 13 pounds of food per day. The tiger needs to consume 195 - 117 = 78 more pounds of food to reach 195 pounds total. At 13 pounds of food per day that's \( \frac{78}{13} \) = 6 more days.
Charlie loaned Monty $1,000 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $84 | |
| $40 | |
| $70 | |
| $24 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.07 x $1,000
i = $70
A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 5 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 116.6 | |
| 117.8 | |
| 108.3 | |
| 94.1 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{5}{100} \) x 6 = \( \frac{5 \times 6}{100} \) = \( \frac{30}{100} \) = 0.3 errors per hour
So, in an average hour, the machine will produce 6 - 0.3 = 5.7 error free parts.
The machine ran for 24 - 5 = 19 hours yesterday so you would expect that 19 x 5.7 = 108.3 error free parts were produced yesterday.