| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
If there were a total of 100 raffle tickets sold and you bought 9 tickets, what's the probability that you'll win the raffle?
| 5% | |
| 17% | |
| 9% | |
| 16% |
You have 9 out of the total of 100 raffle tickets sold so you have a (\( \frac{9}{100} \)) x 100 = \( \frac{9 \times 100}{100} \) = \( \frac{900}{100} \) = 9% chance to win the raffle.
Alex loaned Latoya $500 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $510 | |
| $515 | |
| $530 | |
| $535 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.06 x $500
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $500 + $30A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 8 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 156.8 | |
| 139.7 | |
| 76 | |
| 95 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{5}{100} \) x 5 = \( \frac{5 \times 5}{100} \) = \( \frac{25}{100} \) = 0.25 errors per hour
So, in an average hour, the machine will produce 5 - 0.25 = 4.75 error free parts.
The machine ran for 24 - 8 = 16 hours yesterday so you would expect that 16 x 4.75 = 76 error free parts were produced yesterday.
Simplify \( \sqrt{125} \)
| 2\( \sqrt{10} \) | |
| 5\( \sqrt{5} \) | |
| 7\( \sqrt{10} \) | |
| 4\( \sqrt{5} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)
What is 6b5 + 2b5?
| -4b5 | |
| 8b5 | |
| 4b5 | |
| 4b-5 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
6b5 + 2b5
(6 + 2)b5
8b5