| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
If a mayor is elected with 75% of the votes cast and 77% of a town's 49,000 voters cast a vote, how many votes did the mayor receive?
| 23,393 | |
| 27,543 | |
| 28,298 | |
| 30,184 |
If 77% of the town's 49,000 voters cast ballots the number of votes cast is:
(\( \frac{77}{100} \)) x 49,000 = \( \frac{3,773,000}{100} \) = 37,730
The mayor got 75% of the votes cast which is:
(\( \frac{75}{100} \)) x 37,730 = \( \frac{2,829,750}{100} \) = 28,298 votes.
What is \( \frac{1}{5} \) x \( \frac{1}{8} \)?
| \(\frac{1}{36}\) | |
| \(\frac{1}{5}\) | |
| \(\frac{12}{49}\) | |
| \(\frac{1}{40}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{5} \) x \( \frac{1}{8} \) = \( \frac{1 x 1}{5 x 8} \) = \( \frac{1}{40} \) = \(\frac{1}{40}\)
What is -5z7 - 5z7?
| 49 | |
| -10z7 | |
| -14 | |
| 10z-7 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-5z7 - 5z7
(-5 - 5)z7
-10z7
If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?
| 128 m2 | |
| 32 m2 | |
| 98 m2 | |
| 72 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.
Putting these two equations together and solving for width (w):
2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4
Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 49:2 | |
| 3:8 | |
| 9:6 | |
| 3:4 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.