| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.46 |
| Score | 0% | 69% |
The total water usage for a city is 40,000 gallons each day. Of that total, 20% is for personal use and 53% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 1,250 | |
| 2,700 | |
| 13,200 | |
| 12,400 |
53% of the water consumption is industrial use and 20% is personal use so (53% - 20%) = 33% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{33}{100} \) x 40,000 gallons = 13,200 gallons.
Solve for \( \frac{6!}{3!} \)
| \( \frac{1}{8} \) | |
| \( \frac{1}{30} \) | |
| 120 | |
| \( \frac{1}{9} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{6!}{3!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{6 \times 5 \times 4}{1} \)
\( 6 \times 5 \times 4 \)
120
Convert x-3 to remove the negative exponent.
| \( \frac{-3}{x} \) | |
| \( \frac{-1}{-3x} \) | |
| \( \frac{1}{x^3} \) | |
| \( \frac{3}{x} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Ezra loaned Ezra $1,000 at an annual interest rate of 5%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $18 | |
| $28 | |
| $50 | |
| $56 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.05 x $1,000
i = $50
Which of the following is not an integer?
\({1 \over 2}\) |
|
0 |
|
-1 |
|
1 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.