ASVAB Arithmetic Reasoning Practice Test 954772 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

Which of the following is a mixed number?

82% Answer Correctly

\({5 \over 7} \)

\({a \over 5} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

Find the average of the following numbers: 13, 9, 13, 9.

74% Answer Correctly
10
11
6
12

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{13 + 9 + 13 + 9}{4} \) = \( \frac{44}{4} \) = 11


3

What is \( 6 \)\( \sqrt{12} \) + \( 5 \)\( \sqrt{3} \)

35% Answer Correctly
30\( \sqrt{12} \)
30\( \sqrt{36} \)
11\( \sqrt{3} \)
17\( \sqrt{3} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{12} \) + 5\( \sqrt{3} \)
6\( \sqrt{4 \times 3} \) + 5\( \sqrt{3} \)
6\( \sqrt{2^2 \times 3} \) + 5\( \sqrt{3} \)
(6)(2)\( \sqrt{3} \) + 5\( \sqrt{3} \)
12\( \sqrt{3} \) + 5\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{3} \) + 5\( \sqrt{3} \)
(12 + 5)\( \sqrt{3} \)
17\( \sqrt{3} \)


4

What is \( \frac{9y^6}{2y^4} \)?

60% Answer Correctly
4\(\frac{1}{2}\)y2
4\(\frac{1}{2}\)y-2
4\(\frac{1}{2}\)y24
\(\frac{2}{9}\)y10

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{9y^6}{2y^4} \)
\( \frac{9}{2} \) y(6 - 4)
4\(\frac{1}{2}\)y2


5

If a car travels 40 miles in 2 hours, what is the average speed?

86% Answer Correctly
65 mph
55 mph
30 mph
20 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{40mi}{2h} \)
20 mph