ASVAB Arithmetic Reasoning Practice Test 957002 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?

52% Answer Correctly
2
3
2
4

Solution

To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2


2

A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 8 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
93.1
183.3
186
147.2

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{3}{100} \) x 6 = \( \frac{3 \times 6}{100} \) = \( \frac{18}{100} \) = 0.18 errors per hour

So, in an average hour, the machine will produce 6 - 0.18 = 5.82 error free parts.

The machine ran for 24 - 8 = 16 hours yesterday so you would expect that 16 x 5.82 = 93.1 error free parts were produced yesterday.


3

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common multiple

greatest common factor

least common multiple

absolute value


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


4

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

least common multiple

absolute value

least common factor

greatest common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


5

Solve for \( \frac{2!}{6!} \)

67% Answer Correctly
5
6
\( \frac{1}{360} \)
\( \frac{1}{60480} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)