ASVAB Arithmetic Reasoning Practice Test 958958 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

What is (b3)2?

80% Answer Correctly
2b3
b6
3b2
b-1

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(b3)2
b(3 * 2)
b6


2

If there were a total of 250 raffle tickets sold and you bought 5 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
12%
10%
2%
8%

Solution

You have 5 out of the total of 250 raffle tickets sold so you have a (\( \frac{5}{250} \)) x 100 = \( \frac{5 \times 100}{250} \) = \( \frac{500}{250} \) = 2% chance to win the raffle.


3

If \( \left|a - 1\right| \) - 7 = 9, which of these is a possible value for a?

62% Answer Correctly
-15
-14
-2
15

Solution

First, solve for \( \left|a - 1\right| \):

\( \left|a - 1\right| \) - 7 = 9
\( \left|a - 1\right| \) = 9 + 7
\( \left|a - 1\right| \) = 16

The value inside the absolute value brackets can be either positive or negative so (a - 1) must equal + 16 or -16 for \( \left|a - 1\right| \) to equal 16:

a - 1 = 16
a = 16 + 1
a = 17
a - 1 = -16
a = -16 + 1
a = -15

So, a = -15 or a = 17.


4

How many 12-passenger vans will it take to drive all 65 members of the football team to an away game?

81% Answer Correctly
6 vans
7 vans
9 vans
3 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{65}{12} \) = 5\(\frac{5}{12}\)

So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.


5

What is \( \frac{2}{4} \) + \( \frac{2}{12} \)?

59% Answer Correctly
\( \frac{2}{12} \)
\(\frac{2}{3}\)
1 \( \frac{5}{8} \)
1 \( \frac{4}{12} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 3}{4 x 3} \) + \( \frac{2 x 1}{12 x 1} \)

\( \frac{6}{12} \) + \( \frac{2}{12} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{6 + 2}{12} \) = \( \frac{8}{12} \) = \(\frac{2}{3}\)