| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
Solve for \( \frac{5!}{3!} \)
| 20 | |
| \( \frac{1}{6720} \) | |
| \( \frac{1}{4} \) | |
| 60480 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{3!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{5 \times 4}{1} \)
\( 5 \times 4 \)
20
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
|
\({2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
If there were a total of 150 raffle tickets sold and you bought 3 tickets, what's the probability that you'll win the raffle?
| 10% | |
| 8% | |
| 15% | |
| 2% |
You have 3 out of the total of 150 raffle tickets sold so you have a (\( \frac{3}{150} \)) x 100 = \( \frac{3 \times 100}{150} \) = \( \frac{300}{150} \) = 2% chance to win the raffle.
How many 6-passenger vans will it take to drive all 66 members of the football team to an away game?
| 12 vans | |
| 5 vans | |
| 8 vans | |
| 11 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{66}{6} \) = 11
Solve 5 + (5 + 2) ÷ 5 x 3 - 42
| 3\(\frac{1}{2}\) | |
| \(\frac{3}{4}\) | |
| -6\(\frac{4}{5}\) | |
| \(\frac{2}{9}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (5 + 2) ÷ 5 x 3 - 42
P: 5 + (7) ÷ 5 x 3 - 42
E: 5 + 7 ÷ 5 x 3 - 16
MD: 5 + \( \frac{7}{5} \) x 3 - 16
MD: 5 + \( \frac{21}{5} \) - 16
AS: \( \frac{25}{5} \) + \( \frac{21}{5} \) - 16
AS: \( \frac{46}{5} \) - 16
AS: \( \frac{46 - 80}{5} \)
\( \frac{-34}{5} \)
-6\(\frac{4}{5}\)