| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 10 | |
| 6 | |
| 5 | |
| 8 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5
Solve 3 + (3 + 3) ÷ 5 x 2 - 22
| 1\(\frac{1}{2}\) | |
| 1\(\frac{1}{7}\) | |
| 3\(\frac{1}{2}\) | |
| 1\(\frac{2}{5}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (3 + 3) ÷ 5 x 2 - 22
P: 3 + (6) ÷ 5 x 2 - 22
E: 3 + 6 ÷ 5 x 2 - 4
MD: 3 + \( \frac{6}{5} \) x 2 - 4
MD: 3 + \( \frac{12}{5} \) - 4
AS: \( \frac{15}{5} \) + \( \frac{12}{5} \) - 4
AS: \( \frac{27}{5} \) - 4
AS: \( \frac{27 - 20}{5} \)
\( \frac{7}{5} \)
1\(\frac{2}{5}\)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?
| 37\(\frac{1}{2}\)% | |
| 35% | |
| 15% | |
| 25% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%
What is the least common multiple of 4 and 10?
| 20 | |
| 13 | |
| 22 | |
| 8 |
The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [20, 40, 60, 80] making 20 the smallest multiple 4 and 10 have in common.
Convert a-4 to remove the negative exponent.
| \( \frac{1}{a^4} \) | |
| \( \frac{-1}{-4a^{4}} \) | |
| \( \frac{-1}{a^{-4}} \) | |
| \( \frac{4}{a} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.