| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
What is \( \frac{1}{5} \) x \( \frac{1}{8} \)?
| \(\frac{4}{25}\) | |
| \(\frac{2}{27}\) | |
| \(\frac{1}{40}\) | |
| \(\frac{1}{6}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{5} \) x \( \frac{1}{8} \) = \( \frac{1 x 1}{5 x 8} \) = \( \frac{1}{40} \) = \(\frac{1}{40}\)
Cooks are needed to prepare for a large party. Each cook can bake either 3 large cakes or 17 small cakes per hour. The kitchen is available for 2 hours and 23 large cakes and 220 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 5 | |
| 11 | |
| 12 | |
| 10 |
If a single cook can bake 3 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 3 x 2 = 6 large cakes during that time. 23 large cakes are needed for the party so \( \frac{23}{6} \) = 3\(\frac{5}{6}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 17 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 17 x 2 = 34 small cakes during that time. 220 small cakes are needed for the party so \( \frac{220}{34} \) = 6\(\frac{8}{17}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 4 + 7 = 11 cooks.
What is -6c2 - 4c2?
| 10c-2 | |
| -2c-4 | |
| -10c2 | |
| 10c2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-6c2 - 4c2
(-6 - 4)c2
-10c2
What is \( \frac{-4b^5}{1b^3} \)?
| -4b\(\frac{3}{5}\) | |
| -4b2 | |
| -4b-2 | |
| -\(\frac{1}{4}\)b-2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-4b^5}{b^3} \)
\( \frac{-4}{1} \) b(5 - 3)
-4b2
Solve for \( \frac{3!}{5!} \)
| \( \frac{1}{210} \) | |
| \( \frac{1}{20} \) | |
| 5 | |
| 504 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)