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guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{65}{100} \) = \( \frac{65 x 30}{100} \) = \( \frac{1950}{100} \) = 19 shots

The center makes 50% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{19}{\frac{50}{100}} \) = 19 x \( \frac{100}{50} \) = \( \frac{19 x 100}{50} \) = \( \frac{1900}{50} \) = 38 shots

to make the same number of shots as the guard and thus score the same number of points.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 16 are [16, 32, 48, 64, 80, 96]. The first few multiples they share are [16, 32, 48, 64, 80] making 16 the smallest multiple 8 and 16 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 2}{8 x 2} \) - \( \frac{8 x 1}{16 x 1} \)

\( \frac{18}{16} \) - \( \frac{8}{16} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{18 - 8}{16} \) = \( \frac{10}{16} \) = \(\frac{5}{8}\)

First, solve for \( \left|b + 7\right| \):

\( \left|b + 7\right| \) + 0 = 1
\( \left|b + 7\right| \) = 1 + 0
\( \left|b + 7\right| \) = 1

The value inside the absolute value brackets can be either positive or negative so (b + 7) must equal + 1 or -1 for \( \left|b + 7\right| \) to equal 1:

So, b = -8 or b = -6.

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{10\sqrt{20}}{2\sqrt{5}} \)
\( \frac{10}{2} \) \( \sqrt{\frac{20}{5}} \)
5 \( \sqrt{4} \)