| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
What is 9z7 x z3?
| 9z21 | |
| 10z21 | |
| 9z10 | |
| 9z3 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
9z7 x z3
(9 x 1)z(7 + 3)
9z10
What is \( \frac{2}{8} \) + \( \frac{7}{12} \)?
| \(\frac{5}{6}\) | |
| 2 \( \frac{7}{24} \) | |
| 1 \( \frac{1}{24} \) | |
| 2 \( \frac{3}{24} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 3}{8 x 3} \) + \( \frac{7 x 2}{12 x 2} \)
\( \frac{6}{24} \) + \( \frac{14}{24} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{6 + 14}{24} \) = \( \frac{20}{24} \) = \(\frac{5}{6}\)
| 0.8 | |
| 2.4 | |
| 1 | |
| 3.2 |
1
If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?
| 1 | |
| 15 | |
| 7 | |
| 9 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 5 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 5 x 3 = 15 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 15 - 6 = 9 new staff for the busy season.
How many 2 gallon cans worth of fuel would you need to pour into an empty 12 gallon tank to fill it exactly halfway?
| 3 | |
| 4 | |
| 7 | |
| 6 |
To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{6 \text{ gallons}}{2 \text{ gallons}} \) = 3