ASVAB Arithmetic Reasoning Practice Test 963615 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

11 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
44
2
41
1

Solution

There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 11 people needing transportation leaving 11 - 9 = 2 who will have to find other transportation.


2

Simplify \( \sqrt{75} \)

62% Answer Correctly
5\( \sqrt{3} \)
4\( \sqrt{6} \)
6\( \sqrt{6} \)
7\( \sqrt{6} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{75} \)
\( \sqrt{25 \times 3} \)
\( \sqrt{5^2 \times 3} \)
5\( \sqrt{3} \)


3

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = -7

none of these is correct

a = 7 or a = -7

a = 7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


4

If there were a total of 200 raffle tickets sold and you bought 8 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
4%
5%
1%
8%

Solution

You have 8 out of the total of 200 raffle tickets sold so you have a (\( \frac{8}{200} \)) x 100 = \( \frac{8 \times 100}{200} \) = \( \frac{800}{200} \) = 4% chance to win the raffle.


5

A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 3 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
150.7
163
92.1
119.7

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{3}{100} \) x 8 = \( \frac{3 \times 8}{100} \) = \( \frac{24}{100} \) = 0.24 errors per hour

So, in an average hour, the machine will produce 8 - 0.24 = 7.76 error free parts.

The machine ran for 24 - 3 = 21 hours yesterday so you would expect that 21 x 7.76 = 163 error free parts were produced yesterday.