ASVAB Arithmetic Reasoning Practice Test 971916 Results

Your Results Global Average
Questions 5 5
Correct 0 2.73
Score 0% 55%

Review

1

If a mayor is elected with 84% of the votes cast and 32% of a town's 44,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
10,138
9,715
11,827
12,531

Solution

If 32% of the town's 44,000 voters cast ballots the number of votes cast is:

(\( \frac{32}{100} \)) x 44,000 = \( \frac{1,408,000}{100} \) = 14,080

The mayor got 84% of the votes cast which is:

(\( \frac{84}{100} \)) x 14,080 = \( \frac{1,182,720}{100} \) = 11,827 votes.


2

53% Answer Correctly
1.8
3.5
1
3.2

Solution


1


3

If a rectangle is twice as long as it is wide and has a perimeter of 36 meters, what is the area of the rectangle?

47% Answer Correctly
8 m2
50 m2
72 m2
98 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 36 meters so the equation becomes: 2w + 2h = 36.

Putting these two equations together and solving for width (w):

2w + 2h = 36
w + h = \( \frac{36}{2} \)
w + h = 18
w = 18 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 18 - 2w
3w = 18
w = \( \frac{18}{3} \)
w = 6

Since h = 2w that makes h = (2 x 6) = 12 and the area = h x w = 6 x 12 = 72 m2


4

The total water usage for a city is 40,000 gallons each day. Of that total, 22% is for personal use and 47% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
2,850
10,000
3,400
12,150

Solution

47% of the water consumption is industrial use and 22% is personal use so (47% - 22%) = 25% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{25}{100} \) x 40,000 gallons = 10,000 gallons.


5

What is -8y5 + 6y5?

66% Answer Correctly
-2y10
14y5
-2y5
-2y25

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-8y5 + 6y5
(-8 + 6)y5
-2y5