| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
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greatest common factor |
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least common multiple |
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absolute value |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is 3b6 - 8b6?
| 11b36 | |
| 5b6 | |
| -5b6 | |
| 11b-12 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
3b6 - 8b6
(3 - 8)b6
-5b6
Which of the following is an improper fraction?
\({a \over 5} \) |
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\(1 {2 \over 5} \) |
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\({2 \over 5} \) |
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\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
If \( \left|x - 4\right| \) + 6 = 9, which of these is a possible value for x?
| -2 | |
| -12 | |
| 1 | |
| 10 |
First, solve for \( \left|x - 4\right| \):
\( \left|x - 4\right| \) + 6 = 9
\( \left|x - 4\right| \) = 9 - 6
\( \left|x - 4\right| \) = 3
The value inside the absolute value brackets can be either positive or negative so (x - 4) must equal + 3 or -3 for \( \left|x - 4\right| \) to equal 3:
| x - 4 = 3 x = 3 + 4 x = 7 | x - 4 = -3 x = -3 + 4 x = 1 |
So, x = 1 or x = 7.
If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 3 | |
| 12 | |
| 13 | |
| 15 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 18 - 6 = 12 new staff for the busy season.