| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
A triathlon course includes a 100m swim, a 20.5km bike ride, and a 16.4km run. What is the total length of the race course?
| 37km | |
| 46.8km | |
| 39.3km | |
| 44km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 20.5km + 16.4km
total distance = 37km
Solve 3 + (3 + 4) ÷ 3 x 2 - 42
| 1\(\frac{1}{3}\) | |
| \(\frac{2}{5}\) | |
| -8\(\frac{1}{3}\) | |
| \(\frac{3}{5}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (3 + 4) ÷ 3 x 2 - 42
P: 3 + (7) ÷ 3 x 2 - 42
E: 3 + 7 ÷ 3 x 2 - 16
MD: 3 + \( \frac{7}{3} \) x 2 - 16
MD: 3 + \( \frac{14}{3} \) - 16
AS: \( \frac{9}{3} \) + \( \frac{14}{3} \) - 16
AS: \( \frac{23}{3} \) - 16
AS: \( \frac{23 - 48}{3} \)
\( \frac{-25}{3} \)
-8\(\frac{1}{3}\)
Convert 4,655,000 to scientific notation.
| 4.655 x 10-6 | |
| 0.466 x 107 | |
| 4.655 x 106 | |
| 4.655 x 10-5 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
4,655,000 in scientific notation is 4.655 x 106
A circular logo is enlarged to fit the lid of a jar. The new diameter is 40% larger than the original. By what percentage has the area of the logo increased?
| 35% | |
| 20% | |
| 15% | |
| 22\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 40% the radius (and, consequently, the total area) increases by \( \frac{40\text{%}}{2} \) = 20%
The total water usage for a city is 5,000 gallons each day. Of that total, 15% is for personal use and 29% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 7,650 | |
| 700 | |
| 13,050 | |
| 9,450 |
29% of the water consumption is industrial use and 15% is personal use so (29% - 15%) = 14% more water is used for industrial purposes. 5,000 gallons are consumed daily so industry consumes \( \frac{14}{100} \) x 5,000 gallons = 700 gallons.