ASVAB Arithmetic Reasoning Practice Test 975401 Results

Your Results Global Average
Questions 5 5
Correct 0 2.75
Score 0% 55%

Review

1

What is \( 7 \)\( \sqrt{45} \) - \( 4 \)\( \sqrt{5} \)

38% Answer Correctly
17\( \sqrt{5} \)
28\( \sqrt{225} \)
3\( \sqrt{16} \)
3\( \sqrt{45} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{45} \) - 4\( \sqrt{5} \)
7\( \sqrt{9 \times 5} \) - 4\( \sqrt{5} \)
7\( \sqrt{3^2 \times 5} \) - 4\( \sqrt{5} \)
(7)(3)\( \sqrt{5} \) - 4\( \sqrt{5} \)
21\( \sqrt{5} \) - 4\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

21\( \sqrt{5} \) - 4\( \sqrt{5} \)
(21 - 4)\( \sqrt{5} \)
17\( \sqrt{5} \)


2

Which of the following is not a prime number?

65% Answer Correctly

5

7

9

2


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


3

What is 7\( \sqrt{2} \) x 9\( \sqrt{7} \)?

41% Answer Correctly
63\( \sqrt{7} \)
63\( \sqrt{14} \)
16\( \sqrt{14} \)
63\( \sqrt{9} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

7\( \sqrt{2} \) x 9\( \sqrt{7} \)
(7 x 9)\( \sqrt{2 \times 7} \)
63\( \sqrt{14} \)


4

Convert z-5 to remove the negative exponent.

67% Answer Correctly
\( \frac{1}{z^{-5}} \)
\( \frac{1}{z^5} \)
\( \frac{-1}{-5z^{5}} \)
\( \frac{-1}{-5z} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


5

What is \( \frac{4}{3} \) - \( \frac{3}{11} \)?

61% Answer Correctly
2 \( \frac{8}{13} \)
1\(\frac{2}{33}\)
2 \( \frac{4}{33} \)
1 \( \frac{3}{33} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 11}{3 x 11} \) - \( \frac{3 x 3}{11 x 3} \)

\( \frac{44}{33} \) - \( \frac{9}{33} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{44 - 9}{33} \) = \( \frac{35}{33} \) = 1\(\frac{2}{33}\)