ASVAB Arithmetic Reasoning Practice Test 976706 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

If \( \left|x - 8\right| \) + 1 = -4, which of these is a possible value for x?

62% Answer Correctly
-6
3
-11
-15

Solution

First, solve for \( \left|x - 8\right| \):

\( \left|x - 8\right| \) + 1 = -4
\( \left|x - 8\right| \) = -4 - 1
\( \left|x - 8\right| \) = -5

The value inside the absolute value brackets can be either positive or negative so (x - 8) must equal - 5 or --5 for \( \left|x - 8\right| \) to equal -5:

x - 8 = -5
x = -5 + 8
x = 3
x - 8 = 5
x = 5 + 8
x = 13

So, x = 13 or x = 3.


2

What is \( \frac{3}{6} \) ÷ \( \frac{4}{9} \)?

68% Answer Correctly
1\(\frac{1}{8}\)
6\(\frac{3}{4}\)
\(\frac{1}{28}\)
\(\frac{1}{6}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{3}{6} \) ÷ \( \frac{4}{9} \) = \( \frac{3}{6} \) x \( \frac{9}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{6} \) x \( \frac{9}{4} \) = \( \frac{3 x 9}{6 x 4} \) = \( \frac{27}{24} \) = 1\(\frac{1}{8}\)


3

A bread recipe calls for 2\(\frac{3}{4}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?

62% Answer Correctly
1\(\frac{5}{8}\) cups
1\(\frac{1}{2}\) cups
1\(\frac{1}{4}\) cups
2\(\frac{1}{8}\) cups

Solution

The amount of flour you need is (2\(\frac{3}{4}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{22}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{13}{8} \) cups
1\(\frac{5}{8}\) cups


4

Solve for \( \frac{5!}{4!} \)

66% Answer Correctly
5
\( \frac{1}{6720} \)
\( \frac{1}{60480} \)
\( \frac{1}{15120} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{5!}{4!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{5}{1} \)
5


5

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 37,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
27,750
33,750
25,833
30,833

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

37,000 fans x \( \frac{5}{6} \) = \( \frac{185000}{6} \) = 30,833 fans.