ASVAB Arithmetic Reasoning Practice Test 977405 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

Bob loaned Charlie $200 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$12
$90
$16
$32

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $200
i = 0.06 x $200
i = $12


2

What is \( \sqrt{\frac{16}{36}} \)?

70% Answer Correctly
\(\frac{2}{3}\)
1\(\frac{4}{5}\)
1
1\(\frac{3}{4}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{16}{36}} \)
\( \frac{\sqrt{16}}{\sqrt{36}} \)
\( \frac{\sqrt{4^2}}{\sqrt{6^2}} \)
\(\frac{2}{3}\)


3

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

59% Answer Correctly

distributive

PEDMAS

associative

commutative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


4

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

improper fraction

mixed number

fraction

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


5

A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 5 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
101.9
146.9
130.2
106.7

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{3}{100} \) x 5 = \( \frac{3 \times 5}{100} \) = \( \frac{15}{100} \) = 0.15 errors per hour

So, in an average hour, the machine will produce 5 - 0.15 = 4.85 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 4.85 = 106.7 error free parts were produced yesterday.