ASVAB Arithmetic Reasoning Practice Test 978795 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

What is -3z7 x 6z5?

75% Answer Correctly
-18z12
3z7
3z35
3z5

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-3z7 x 6z5
(-3 x 6)z(7 + 5)
-18z12


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Alex buys two shirts, each with a regular price of $35, how much will he pay for both shirts?

57% Answer Correctly
$59.50
$40.25
$10.50
$24.50

Solution

By buying two shirts, Alex will save $35 x \( \frac{30}{100} \) = \( \frac{$35 x 30}{100} \) = \( \frac{$1050}{100} \) = $10.50 on the second shirt.

So, his total cost will be
$35.00 + ($35.00 - $10.50)
$35.00 + $24.50
$59.50


3

Convert 0.0005844 to scientific notation.

63% Answer Correctly
5.844 x 10-3
5.844 x 10-4
58.44 x 10-5
5.844 x 105

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0005844 in scientific notation is 5.844 x 10-4


4

Roger loaned Betty $300 at an annual interest rate of 2%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$315
$327
$306
$309

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $300
i = 0.02 x $300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $300 + $6
total = $306


5

What is \( 8 \)\( \sqrt{125} \) + \( 9 \)\( \sqrt{5} \)

35% Answer Correctly
72\( \sqrt{5} \)
17\( \sqrt{125} \)
49\( \sqrt{5} \)
72\( \sqrt{25} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{125} \) + 9\( \sqrt{5} \)
8\( \sqrt{25 \times 5} \) + 9\( \sqrt{5} \)
8\( \sqrt{5^2 \times 5} \) + 9\( \sqrt{5} \)
(8)(5)\( \sqrt{5} \) + 9\( \sqrt{5} \)
40\( \sqrt{5} \) + 9\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

40\( \sqrt{5} \) + 9\( \sqrt{5} \)
(40 + 9)\( \sqrt{5} \)
49\( \sqrt{5} \)