| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
What is -3z7 x 6z5?
| -18z12 | |
| 3z7 | |
| 3z35 | |
| 3z5 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-3z7 x 6z5
(-3 x 6)z(7 + 5)
-18z12
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Alex buys two shirts, each with a regular price of $35, how much will he pay for both shirts?
| $59.50 | |
| $40.25 | |
| $10.50 | |
| $24.50 |
By buying two shirts, Alex will save $35 x \( \frac{30}{100} \) = \( \frac{$35 x 30}{100} \) = \( \frac{$1050}{100} \) = $10.50 on the second shirt.
So, his total cost will be
$35.00 + ($35.00 - $10.50)
$35.00 + $24.50
$59.50
Convert 0.0005844 to scientific notation.
| 5.844 x 10-3 | |
| 5.844 x 10-4 | |
| 58.44 x 10-5 | |
| 5.844 x 105 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
0.0005844 in scientific notation is 5.844 x 10-4
Roger loaned Betty $300 at an annual interest rate of 2%. If no payments are made, what is the total amount owed at the end of the first year?
| $315 | |
| $327 | |
| $306 | |
| $309 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $300
i = 0.02 x $300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $300 + $6What is \( 8 \)\( \sqrt{125} \) + \( 9 \)\( \sqrt{5} \)
| 72\( \sqrt{5} \) | |
| 17\( \sqrt{125} \) | |
| 49\( \sqrt{5} \) | |
| 72\( \sqrt{25} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{125} \) + 9\( \sqrt{5} \)
8\( \sqrt{25 \times 5} \) + 9\( \sqrt{5} \)
8\( \sqrt{5^2 \times 5} \) + 9\( \sqrt{5} \)
(8)(5)\( \sqrt{5} \) + 9\( \sqrt{5} \)
40\( \sqrt{5} \) + 9\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
40\( \sqrt{5} \) + 9\( \sqrt{5} \)