Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 2.71 |
Score | 0% | 54% |
Which of the following is an improper fraction?
\({2 \over 5} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
1.0 | |
0.8 | |
0.6 | |
1 |
1
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 5 to 2 and the ratio of baseball to basketball cards is 5 to 1, what is the ratio of football to basketball cards?
9:1 | |
9:6 | |
25:2 | |
7:2 |
The ratio of football cards to baseball cards is 5:2 and the ratio of baseball cards to basketball cards is 5:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 25:10 and the ratio of baseball cards to basketball cards as 10:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 25:10, 10:2 which reduces to 25:2.
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
3 | |
4 | |
6 | |
3 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 3
What is 6\( \sqrt{5} \) x 3\( \sqrt{5} \)?
18\( \sqrt{5} \) | |
90 | |
9\( \sqrt{25} \) | |
18\( \sqrt{10} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{5} \) x 3\( \sqrt{5} \)
(6 x 3)\( \sqrt{5 \times 5} \)
18\( \sqrt{25} \)
Now we need to simplify the radical:
18\( \sqrt{25} \)
18\( \sqrt{5^2} \)
(18)(5)
90