| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
What is 9\( \sqrt{6} \) x 3\( \sqrt{7} \)?
| 27\( \sqrt{42} \) | |
| 27\( \sqrt{13} \) | |
| 12\( \sqrt{7} \) | |
| 27\( \sqrt{7} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{6} \) x 3\( \sqrt{7} \)
(9 x 3)\( \sqrt{6 \times 7} \)
27\( \sqrt{42} \)
A tiger in a zoo has consumed 50 pounds of food in 10 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 70 pounds?
| 13 | |
| 2 | |
| 7 | |
| 4 |
If the tiger has consumed 50 pounds of food in 10 days that's \( \frac{50}{10} \) = 5 pounds of food per day. The tiger needs to consume 70 - 50 = 20 more pounds of food to reach 70 pounds total. At 5 pounds of food per day that's \( \frac{20}{5} \) = 4 more days.
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
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integer |
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fraction |
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mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
20 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 4 | |
| 1 | |
| 5 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 20 people needing transportation leaving 20 - 15 = 5 who will have to find other transportation.
What is \( \frac{4}{5} \) + \( \frac{2}{9} \)?
| 1 \( \frac{2}{8} \) | |
| 2 \( \frac{9}{18} \) | |
| 2 \( \frac{3}{45} \) | |
| 1\(\frac{1}{45}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 9}{5 x 9} \) + \( \frac{2 x 5}{9 x 5} \)
\( \frac{36}{45} \) + \( \frac{10}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{36 + 10}{45} \) = \( \frac{46}{45} \) = 1\(\frac{1}{45}\)