Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (5 + 3) ÷ 4 x 4 - 4²
P: 2 + (8) ÷ 4 x 4 - 4²
E: 2 + 8 ÷ 4 x 4 - 16
MD: 2 + \( \frac{8}{4} \) x 4 - 16
MD: 2 + \( \frac{32}{4} \) - 16
AS: \( \frac{8}{4} \) + \( \frac{32}{4} \) - 16
AS: \( \frac{40}{4} \) - 16
AS: \( \frac{40 - 64}{4} \)
\( \frac{-24}{4} \)
-6

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-2a³ - 5a³
(-2 - 5)a³
-7a³

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.

The area of a circle is given by the formula A = πr² where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))². If the diameter of the logo increases by 50% the radius (and, consequently, the total area) increases by \( \frac{50\text{%}}{2} \) = 25%

To add these radicals together their radicands must be the same:

5\( \sqrt{20} \) + 5\( \sqrt{5} \)
5\( \sqrt{4 \times 5} \) + 5\( \sqrt{5} \)
5\( \sqrt{2^2 \times 5} \) + 5\( \sqrt{5} \)
(5)(2)\( \sqrt{5} \) + 5\( \sqrt{5} \)
10\( \sqrt{5} \) + 5\( \sqrt{5} \)

Now that the radicands are identical, you can add them together: