Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (3 + 5) ÷ 3 x 3 - 4²
P: 3 + (8) ÷ 3 x 3 - 4²
E: 3 + 8 ÷ 3 x 3 - 16
MD: 3 + \( \frac{8}{3} \) x 3 - 16
MD: 3 + \( \frac{24}{3} \) - 16
AS: \( \frac{9}{3} \) + \( \frac{24}{3} \) - 16
AS: \( \frac{33}{3} \) - 16
AS: \( \frac{33 - 48}{3} \)
\( \frac{-15}{3} \)
-5

By buying two shirts, Ezra will save $31 x \( \frac{35}{100} \) = \( \frac{$31 x 35}{100} \) = \( \frac{$1085}{100} \) = $10.85 on the second shirt.

So, his total cost will be
$31.00 + ($31.00 - $10.85)
$31.00 + $20.15
$51.15

First, solve for \( \left|x - 9\right| \):

\( \left|x - 9\right| \) - 5 = -7
\( \left|x - 9\right| \) = -7 + 5
\( \left|x - 9\right| \) = -2

The value inside the absolute value brackets can be either positive or negative so (x - 9) must equal - 2 or --2 for \( \left|x - 9\right| \) to equal -2:

So, x = 11 or x = 7.

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

4z⁶ - 7z⁶
(4 - 7)z⁶
-3z⁶

To add these radicals together their radicands must be the same:

6\( \sqrt{50} \) + 3\( \sqrt{2} \)
6\( \sqrt{25 \times 2} \) + 3\( \sqrt{2} \)
6\( \sqrt{5^2 \times 2} \) + 3\( \sqrt{2} \)
(6)(5)\( \sqrt{2} \) + 3\( \sqrt{2} \)
30\( \sqrt{2} \) + 3\( \sqrt{2} \)

Now that the radicands are identical, you can add them together: