| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 44,000 seats in a stadium are filled, how many home fans are in attendance?
| 37,600 | |
| 36,667 | |
| 31,200 | |
| 30,400 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
44,000 fans x \( \frac{5}{6} \) = \( \frac{220000}{6} \) = 36,667 fans.
How many 13-passenger vans will it take to drive all 62 members of the football team to an away game?
| 6 vans | |
| 5 vans | |
| 7 vans | |
| 21 |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{62}{13} \) = 4\(\frac{10}{13}\)
So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.
What is 8\( \sqrt{7} \) x 5\( \sqrt{4} \)?
| 13\( \sqrt{7} \) | |
| 40\( \sqrt{7} \) | |
| 80\( \sqrt{7} \) | |
| 13\( \sqrt{28} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{7} \) x 5\( \sqrt{4} \)
(8 x 5)\( \sqrt{7 \times 4} \)
40\( \sqrt{28} \)
Now we need to simplify the radical:
40\( \sqrt{28} \)
40\( \sqrt{7 \times 4} \)
40\( \sqrt{7 \times 2^2} \)
(40)(2)\( \sqrt{7} \)
80\( \sqrt{7} \)
A triathlon course includes a 400m swim, a 40.7km bike ride, and a 6.2km run. What is the total length of the race course?
| 47.3km | |
| 31.7km | |
| 45.6km | |
| 39.3km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.4km + 40.7km + 6.2km
total distance = 47.3km
Roger loaned Roger $1,400 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $84 | |
| $49 | |
| $81 | |
| $98 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.07 x $1,400
i = $98