| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
What is \( \frac{2}{9} \) x \( \frac{2}{6} \)?
| \(\frac{2}{27}\) | |
| \(\frac{4}{9}\) | |
| \(\frac{1}{5}\) | |
| \(\frac{8}{35}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{9} \) x \( \frac{2}{6} \) = \( \frac{2 x 2}{9 x 6} \) = \( \frac{4}{54} \) = \(\frac{2}{27}\)
Frank loaned April $1,100 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,177 | |
| $1,144 | |
| $1,111 | |
| $1,166 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,100
i = 0.06 x $1,100
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,100 + $66Find the average of the following numbers: 18, 10, 17, 11.
| 15 | |
| 18 | |
| 14 | |
| 16 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{18 + 10 + 17 + 11}{4} \) = \( \frac{56}{4} \) = 14
What is \( \frac{7}{3} \) - \( \frac{3}{11} \)?
| 1 \( \frac{6}{12} \) | |
| 2\(\frac{2}{33}\) | |
| 1 \( \frac{1}{33} \) | |
| \( \frac{6}{12} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 11}{3 x 11} \) - \( \frac{3 x 3}{11 x 3} \)
\( \frac{77}{33} \) - \( \frac{9}{33} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{77 - 9}{33} \) = \( \frac{68}{33} \) = 2\(\frac{2}{33}\)
What is \( 5 \)\( \sqrt{28} \) + \( 6 \)\( \sqrt{7} \)
| 11\( \sqrt{28} \) | |
| 16\( \sqrt{7} \) | |
| 30\( \sqrt{7} \) | |
| 11\( \sqrt{7} \) |
To add these radicals together their radicands must be the same:
5\( \sqrt{28} \) + 6\( \sqrt{7} \)
5\( \sqrt{4 \times 7} \) + 6\( \sqrt{7} \)
5\( \sqrt{2^2 \times 7} \) + 6\( \sqrt{7} \)
(5)(2)\( \sqrt{7} \) + 6\( \sqrt{7} \)
10\( \sqrt{7} \) + 6\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
10\( \sqrt{7} \) + 6\( \sqrt{7} \)