ASVAB Arithmetic Reasoning Practice Test 988084 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

What is \( \frac{2}{9} \) x \( \frac{2}{6} \)?

72% Answer Correctly
\(\frac{2}{27}\)
\(\frac{4}{9}\)
\(\frac{1}{5}\)
\(\frac{8}{35}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{9} \) x \( \frac{2}{6} \) = \( \frac{2 x 2}{9 x 6} \) = \( \frac{4}{54} \) = \(\frac{2}{27}\)


2

Frank loaned April $1,100 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$1,177
$1,144
$1,111
$1,166

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,100
i = 0.06 x $1,100

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,100 + $66
total = $1,166


3

Find the average of the following numbers: 18, 10, 17, 11.

74% Answer Correctly
15
18
14
16

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{18 + 10 + 17 + 11}{4} \) = \( \frac{56}{4} \) = 14


4

What is \( \frac{7}{3} \) - \( \frac{3}{11} \)?

61% Answer Correctly
1 \( \frac{6}{12} \)
2\(\frac{2}{33}\)
1 \( \frac{1}{33} \)
\( \frac{6}{12} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 11}{3 x 11} \) - \( \frac{3 x 3}{11 x 3} \)

\( \frac{77}{33} \) - \( \frac{9}{33} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{77 - 9}{33} \) = \( \frac{68}{33} \) = 2\(\frac{2}{33}\)


5

What is \( 5 \)\( \sqrt{28} \) + \( 6 \)\( \sqrt{7} \)

35% Answer Correctly
11\( \sqrt{28} \)
16\( \sqrt{7} \)
30\( \sqrt{7} \)
11\( \sqrt{7} \)

Solution

To add these radicals together their radicands must be the same:

5\( \sqrt{28} \) + 6\( \sqrt{7} \)
5\( \sqrt{4 \times 7} \) + 6\( \sqrt{7} \)
5\( \sqrt{2^2 \times 7} \) + 6\( \sqrt{7} \)
(5)(2)\( \sqrt{7} \) + 6\( \sqrt{7} \)
10\( \sqrt{7} \) + 6\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

10\( \sqrt{7} \) + 6\( \sqrt{7} \)
(10 + 6)\( \sqrt{7} \)
16\( \sqrt{7} \)