| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Which of the following is an improper fraction?
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
The total water usage for a city is 5,000 gallons each day. Of that total, 12% is for personal use and 35% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 4,500 | |
| 1,150 | |
| 1,100 | |
| 12,400 |
35% of the water consumption is industrial use and 12% is personal use so (35% - 12%) = 23% more water is used for industrial purposes. 5,000 gallons are consumed daily so industry consumes \( \frac{23}{100} \) x 5,000 gallons = 1,150 gallons.
What is \( \frac{-1x^9}{1x^2} \)?
| -x\(\frac{2}{9}\) | |
| -x7 | |
| -x18 | |
| -x-7 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-x^9}{x^2} \)
\( \frac{-1}{1} \) x(9 - 2)
-x7
What is 2\( \sqrt{5} \) x 5\( \sqrt{8} \)?
| 7\( \sqrt{5} \) | |
| 20\( \sqrt{10} \) | |
| 10\( \sqrt{13} \) | |
| 10\( \sqrt{5} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{5} \) x 5\( \sqrt{8} \)
(2 x 5)\( \sqrt{5 \times 8} \)
10\( \sqrt{40} \)
Now we need to simplify the radical:
10\( \sqrt{40} \)
10\( \sqrt{10 \times 4} \)
10\( \sqrt{10 \times 2^2} \)
(10)(2)\( \sqrt{10} \)
20\( \sqrt{10} \)
What is \( 9 \)\( \sqrt{125} \) - \( 7 \)\( \sqrt{5} \)
| 38\( \sqrt{5} \) | |
| 63\( \sqrt{25} \) | |
| 2\( \sqrt{5} \) | |
| 2\( \sqrt{625} \) |
To subtract these radicals together their radicands must be the same:
9\( \sqrt{125} \) - 7\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) - 7\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) - 7\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) - 7\( \sqrt{5} \)
45\( \sqrt{5} \) - 7\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
45\( \sqrt{5} \) - 7\( \sqrt{5} \)