ASVAB Arithmetic Reasoning Practice Test 988276 Results

Your Results Global Average
Questions 5 5
Correct 0 2.70
Score 0% 54%

Review

1

Which of the following is an improper fraction?

70% Answer Correctly

\({2 \over 5} \)

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

The total water usage for a city is 5,000 gallons each day. Of that total, 12% is for personal use and 35% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
4,500
1,150
1,100
12,400

Solution

35% of the water consumption is industrial use and 12% is personal use so (35% - 12%) = 23% more water is used for industrial purposes. 5,000 gallons are consumed daily so industry consumes \( \frac{23}{100} \) x 5,000 gallons = 1,150 gallons.


3

What is \( \frac{-1x^9}{1x^2} \)?

60% Answer Correctly
-x\(\frac{2}{9}\)
-x7
-x18
-x-7

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-x^9}{x^2} \)
\( \frac{-1}{1} \) x(9 - 2)
-x7


4

What is 2\( \sqrt{5} \) x 5\( \sqrt{8} \)?

41% Answer Correctly
7\( \sqrt{5} \)
20\( \sqrt{10} \)
10\( \sqrt{13} \)
10\( \sqrt{5} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

2\( \sqrt{5} \) x 5\( \sqrt{8} \)
(2 x 5)\( \sqrt{5 \times 8} \)
10\( \sqrt{40} \)

Now we need to simplify the radical:

10\( \sqrt{40} \)
10\( \sqrt{10 \times 4} \)
10\( \sqrt{10 \times 2^2} \)
(10)(2)\( \sqrt{10} \)
20\( \sqrt{10} \)


5

What is \( 9 \)\( \sqrt{125} \) - \( 7 \)\( \sqrt{5} \)

39% Answer Correctly
38\( \sqrt{5} \)
63\( \sqrt{25} \)
2\( \sqrt{5} \)
2\( \sqrt{625} \)

Solution

To subtract these radicals together their radicands must be the same:

9\( \sqrt{125} \) - 7\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) - 7\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) - 7\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) - 7\( \sqrt{5} \)
45\( \sqrt{5} \) - 7\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

45\( \sqrt{5} \) - 7\( \sqrt{5} \)
(45 - 7)\( \sqrt{5} \)
38\( \sqrt{5} \)