| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.78 |
| Score | 0% | 76% |
What is the distance in miles of a trip that takes 9 hours at an average speed of 70 miles per hour?
| 135 miles | |
| 630 miles | |
| 320 miles | |
| 75 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 70mph \times 9h \)
630 miles
What is the next number in this sequence: 1, 8, 15, 22, 29, __________ ?
| 42 | |
| 36 | |
| 45 | |
| 37 |
The equation for this sequence is:
an = an-1 + 7
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 7
a6 = 29 + 7
a6 = 36
Simplify \( \frac{36}{52} \).
| \( \frac{7}{12} \) | |
| \( \frac{9}{13} \) | |
| \( \frac{5}{18} \) | |
| \( \frac{8}{11} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{36}{52} \) = \( \frac{\frac{36}{4}}{\frac{52}{4}} \) = \( \frac{9}{13} \)
A triathlon course includes a 400m swim, a 50.6km bike ride, and a 13.100000000000001km run. What is the total length of the race course?
| 50.9km | |
| 64.1km | |
| 29.6km | |
| 50.3km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.4km + 50.6km + 13.100000000000001km
total distance = 64.1km
If all of a roofing company's 8 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 9 | |
| 17 | |
| 3 | |
| 16 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 2 crews so there are \( \frac{8}{2} \) = 4 workers on a crew. 6 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 6 x 4 = 24 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 24 - 8 = 16 new staff for the busy season.