The equation for this sequence is:

a_n = a_n-1 + 6

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 6
a₆ = 25 + 6
a₆ = 31

The factors of 16 are [1, 2, 4, 8, 16] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 the greatest factor 16 and 56 have in common.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{6 x 5}{2 x 5} \) - \( \frac{4 x 1}{10 x 1} \)

\( \frac{30}{10} \) - \( \frac{4}{10} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{30 - 4}{10} \) = \( \frac{26}{10} \) = 2\(\frac{3}{5}\)

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-8x^9}{5x^2} \)
\( \frac{-8}{5} \) x^{(9 - 2)}
-1\(\frac{3}{5}\)x⁷

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.