| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
4! = ?
5 x 4 x 3 x 2 x 1 |
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4 x 3 |
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4 x 3 x 2 x 1 |
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3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
The __________ is the greatest factor that divides two integers.
greatest common factor |
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absolute value |
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greatest common multiple |
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least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( 5 \)\( \sqrt{20} \) - \( 2 \)\( \sqrt{5} \)
| 3\( \sqrt{4} \) | |
| 10\( \sqrt{5} \) | |
| 10\( \sqrt{4} \) | |
| 8\( \sqrt{5} \) |
To subtract these radicals together their radicands must be the same:
5\( \sqrt{20} \) - 2\( \sqrt{5} \)
5\( \sqrt{4 \times 5} \) - 2\( \sqrt{5} \)
5\( \sqrt{2^2 \times 5} \) - 2\( \sqrt{5} \)
(5)(2)\( \sqrt{5} \) - 2\( \sqrt{5} \)
10\( \sqrt{5} \) - 2\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
10\( \sqrt{5} \) - 2\( \sqrt{5} \)A tiger in a zoo has consumed 72 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 108 pounds?
| 3 | |
| 2 | |
| 6 | |
| 9 |
If the tiger has consumed 72 pounds of food in 6 days that's \( \frac{72}{6} \) = 12 pounds of food per day. The tiger needs to consume 108 - 72 = 36 more pounds of food to reach 108 pounds total. At 12 pounds of food per day that's \( \frac{36}{12} \) = 3 more days.
What is \( \frac{9\sqrt{16}}{3\sqrt{4}} \)?
| \(\frac{1}{4}\) \( \sqrt{\frac{1}{3}} \) | |
| 3 \( \sqrt{4} \) | |
| 3 \( \sqrt{\frac{1}{4}} \) | |
| \(\frac{1}{3}\) \( \sqrt{4} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{9\sqrt{16}}{3\sqrt{4}} \)
\( \frac{9}{3} \) \( \sqrt{\frac{16}{4}} \)
3 \( \sqrt{4} \)