ASVAB Arithmetic Reasoning Practice Test 99265 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

69% Answer Correctly
27
33
31
29

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31


2

A triathlon course includes a 200m swim, a 20.5km bike ride, and a 7.6000000000000005km run. What is the total length of the race course?

69% Answer Correctly
52km
64.2km
28.3km
41.5km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.2km + 20.5km + 7.6000000000000005km
total distance = 28.3km


3

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 42,000 seats in a stadium are filled, how many home fans are in attendance?

49% Answer Correctly
30,000
35,000
31,200
24,750

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

42,000 fans x \( \frac{5}{6} \) = \( \frac{210000}{6} \) = 35,000 fans.


4

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

fraction

improper fraction

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


5

What is \( 7 \)\( \sqrt{8} \) + \( 4 \)\( \sqrt{2} \)

35% Answer Correctly
28\( \sqrt{4} \)
11\( \sqrt{8} \)
18\( \sqrt{2} \)
28\( \sqrt{8} \)

Solution

To add these radicals together their radicands must be the same:

7\( \sqrt{8} \) + 4\( \sqrt{2} \)
7\( \sqrt{4 \times 2} \) + 4\( \sqrt{2} \)
7\( \sqrt{2^2 \times 2} \) + 4\( \sqrt{2} \)
(7)(2)\( \sqrt{2} \) + 4\( \sqrt{2} \)
14\( \sqrt{2} \) + 4\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

14\( \sqrt{2} \) + 4\( \sqrt{2} \)
(14 + 4)\( \sqrt{2} \)
18\( \sqrt{2} \)