If the tiger has consumed 48 pounds of food in 6 days that's \( \frac{48}{6} \) = 8 pounds of food per day. The tiger needs to consume 96 - 48 = 48 more pounds of food to reach 96 pounds total. At 8 pounds of food per day that's \( \frac{48}{8} \) = 6 more days.

To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{7\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 3

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 5}{2 x 5} \) + \( \frac{3 x 1}{10 x 1} \)

\( \frac{10}{10} \) + \( \frac{3}{10} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{10 + 3}{10} \) = \( \frac{13}{10} \) = 1\(\frac{3}{10}\)

The factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 72 and 52 have in common.

Average speed in miles per hour is the number of miles traveled divided by the number of hours: