If the tiger has consumed 60 pounds of food in 10 days that's \( \frac{60}{10} \) = 6 pounds of food per day. The tiger needs to consume 90 - 60 = 30 more pounds of food to reach 90 pounds total. At 6 pounds of food per day that's \( \frac{30}{6} \) = 5 more days.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 6 and 12 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 2}{6 x 2} \) - \( \frac{2 x 1}{12 x 1} \)

\( \frac{4}{12} \) - \( \frac{2}{12} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{4 - 2}{12} \) = \( \frac{2}{12} \) = \(\frac{1}{6}\)

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 5}{6 x 5} \) + \( \frac{6 x 3}{10 x 3} \)

\( \frac{40}{30} \) + \( \frac{18}{30} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{40 + 18}{30} \) = \( \frac{58}{30} \) = 1\(\frac{14}{15}\)

The factors of a number are all positive integers that divide evenly into the number. The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{16\sqrt{16}}{8\sqrt{8}} \)
\( \frac{16}{8} \) \( \sqrt{\frac{16}{8}} \)
2 \( \sqrt{2} \)