ASVAB Electronics Information Practice Test 152415 Results

Your Results Global Average
Questions 5 5
Correct 0 3.82
Score 0% 76%

Review

1

Voltage and current are __________ proportional.

66% Answer Correctly

indirectly

inversely

directly

not


Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.


2

This circuit diagram represents a(n):

68% Answer Correctly

parallel circuit

series circuit

series-parallel circuit

open circuit


Solution

A series circuit has only one path for current to flow. In a series circuit, current (I) is the same throughout the circuit and is equal to the total voltage (V) applied to the circuit divided by the total resistance (R) of the loads in the circuit. The sum of the voltage drops across each resistor in the circuit will equal the total voltage applied to the circuit.


3

Which of the following can conduct electricity under some conditions but not others?

82% Answer Correctly

resistor

conductor

insulator

semiconductor


Solution

Semiconductors have valence shells that are exacly half full and can conduct electricity under some conditions but not others. This property makes them useful for the control of electrical current.


4 A circuit with a 120-volt power supply is protected by a 20-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?
82% Answer Correctly
1200 W
2400 W
2402 W
3600 W

Solution
Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 20A circuit breaker would allow is 120V x 20A = 2400 W.

5 What's the overall power consumption of a piece of equipment that is rated for 7 amps at 30 volts?
80% Answer Correctly
315 W
210 W
70 W
211.5 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 7 amps (I) at 30 volts (V) so the equation becomes P = \( 30 \times 7 \) = 210 W