ASVAB Electronics Information Practice Test 237478 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.51
Score	0%	70%

Review

Using a fuse with a current rating higher than that required by a circuit:

70% Answer Correctly

	is required
	is recommended
	makes no difference
	makes the circuit less safe

Solution

A fuse is a type of low resistance resistor that stops current flow in a circuit in response to a larger than intended electric current flow. Using a fuse with a higher current rating than required by a circuit is less safe as it could potentially allow overcurrent and risk a fire or heat-related equipment damage.

2 Use Ohm's Law to calculate the value of voltage in this circuit if resistance is 40 Ω and current is 5 amps.

85% Answer Correctly

	200 V
	202 V
	300 V
	180 V

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

V = \( I \times R \) = \( 5 \times 40 \) = 200 V

3 Suppose you have 4 [6V 25A] batteries that you can connect together in series, in parallel, or in series-parallel. Which of the following voltage and ampere combinations cannot be attained using these 4 batteries?

46% Answer Correctly

	6V 100A
	24V 25A
	12V 50A
	24V 100A

Solution

Connecting the 4 batteries in series multiplies their voltage while keeping their current the same yielding a 24V 25A configuration. Connecting the 4 batteries in parallel multiplies their current while keeping their voltage the same yielding a 6V 100A configuration. Using a series-parallel connection, 2 batteries can be connected in series and 2 can be connected in parallel resulting in a 12V 50A configuration.

An engineer who wants to document an electric circuit would create which of the following?

67% Answer Correctly

	a blueprint
	a layout
	a schematic
	a matrix

Solution

A schematic is the proper name for a drawing of an electric or electronic circuit.

5 A circuit with a 120-volt power supply is protected by a 5-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

82% Answer Correctly

	1800 W
	602 W
	600 W
	603 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 5A circuit breaker would allow is 120V x 5A = 600 W.