| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
Electrons will flow as current from areas of __________ potential (concentration of electrons) to areas of __________ potential.
low, low |
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high, low |
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high, high |
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low, high |
Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.
The formula specifying Ohm's law is which of the following?
\(V = {R \over I}\) |
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\(V = {I \over R}\) |
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V = IR |
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V = I2R |
Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.
What kind of diode allows current to flow in the opposite direction once a certain voltage threshold is reached?
standard diode |
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v-type diode |
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light emitting diode |
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zener diode |
A diode allows current to pass easily in one direction and blocks current in the other direction. A zener diode is a diode which allows current to flow in one direction as normal and will also allow current flow in the reverse direction when the voltage is above a certain value. This value is called the breakdown voltage.
In electrical wiring, which of the following are proportional?
the diameter of the wire and the amount of the voltage |
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the diameter of the wire and the amount of the current |
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the length of the wire and the amount of the current |
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the length of the wire and the amount of the voltage |
Current flow through a wire increases the temperature of the wire. If too small a wire is used, the wire will heat up causing a loss in conductivity and possibly a fire. The thicker in diameter a wire is, the more current it can carry without overheating.
| 22.5 A | |
| 15 A | |
| 7.5 A | |
| 9 A |
Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.
Solved for current, I = \( \frac{V}{R} \) = \( \frac{75}{10} \) = 7.5 A