ASVAB Electronics Information Practice Test 305244 Results

Your Results Global Average
Questions 5 5
Correct 0 3.69
Score 0% 74%

Review

1

Electrons will flow as current from areas of __________ potential (concentration of electrons) to areas of __________ potential.

74% Answer Correctly

high, low

low, high

high, high

low, low


Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.


2

All electricity is the movement of which subatomic particles?

89% Answer Correctly

neutrons

nuclei

electrons

protons


Solution

All electricity is the movement of electrons which are subatomic particles that orbit the nucleus of an atom. Electrons occupy various energy levels called shells and how well an element enables the flow of electrons depends on how many electrons occupy its outer (valence) electron shell.


3

What is the voltage of most household electrical systems in the United States?

59% Answer Correctly

220V

60Hz

110V

60V


Solution

Most households use electricity with a voltage of 110V.


4

The sum of the voltage drops across each resistor in a __________ circuit will equal the total voltage applied to the circuit.

54% Answer Correctly

series-parallel

closed

series

parallel


Solution

A series circuit has only one path for current to flow. In a series circuit, current (I) is the same throughout the circuit and is equal to the total voltage (V) applied to the circuit divided by the total resistance (R) of the loads in the circuit. The sum of the voltage drops across each resistor in the circuit will equal the total voltage applied to the circuit.


5 What's the overall power consumption of a piece of equipment that is rated for 7 amps at 80 volts?
85% Answer Correctly
1120 W
562 W
559 W
560 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 7 amps (I) at 80 volts (V) so the equation becomes P = \( 80 \times 7 \) = 560 W